Question

determine o valor de limite

Answer 1

Resposta:

$\lim_{x \to- \infty} \frac{x^2-2}{2^x\:+\:2}  \\\\\\\frac{lim_{x \to- \infty} {x^2-2}}{lim_{n \to- \infty} {2^x+2}} \\\\lim_{x \to- \infty} {x^2-2} = \infty  \\\\ e \\lim_{x \to- \infty} {2^x+2} = 2 \\\\\\\\   \lim_{x \to- \infty} \frac{x^2-2}{2^x\:+\:2}  = \frac{\infty}{2} = \infty$

Explicação passo-a-passo: