Question

Determine o valor de
K=(0,999...+1/√0,25)^n onde n= (1/√2 - 1) - (1/√2 + 1)

Answer 1

sendo

k = (0.999.... + 1/√0.25)^n

n = (1/√2 - 1) - (1/√2 + 1) = -2

k = (1 + 1/√(1/4) )^-2

k = (1 + 1/(1/2) )^-2

k = (1 + 2)^-2 = 1/9