Question

determine o valor de cada coeficiente na х²-6× + 5 = 0​

Answer 1

$\boxed{\begin{array}{lr} x^2-6x+5=0 \end{array}}\\\\a=1\\b=-6\\c=5$

Como Pede a Pergunta o

Valor dos Coeficientes fica;

$\boxed{\begin{array}{lr} ax^2-bx+c \end{array}}$

Valor de Delta é 16

$\boxed{\begin{array}{lr} \/ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\\x'=5 \/ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\/ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x''=1\\\/ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\\ \end{array}}$

$\boxed{\begin{array}{lr} S=\{1\ , 5 \} \ \ \ \checkmark \end{array}}$