Matemática, perguntado por gabuchiha, 11 meses atrás

Determine o valor de;​

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Soluções para a tarefa

Respondido por CyberKirito
0

b)

\sin150\degree=\sin30\degree=\dfrac{1}{2}

 \cos150\degree=-\cos30\degree=-\dfrac{\sqrt{3}}{2}

c)

\sin210\degree=-\sin30\degree=-\dfrac{1}{2}

 \cos210\degree=-\cos30\degree=-\dfrac{\sqrt{3}}{2}

\sin240\degree=-\sin60\degree=-\dfrac{\sqrt{3}}{2}

 \cos240\degree=-\cos60\degree=-\dfrac{1}{2}

d)

\sin300\degree=-\sin60\degree=-\dfrac{\sqrt{3}}{2}

 \cos300\degree=\cos60\degree=\dfrac{1}{2}

 \sin330\degree=-\sin30\degree=-\dfrac{1}{2}

 \cos330\degree=\cos30\degree=\dfrac{\sqrt{3}}{2}

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