Question

determine o valor das expressões abaixo: [(3^2)^3-3√-27]*(1/7)^-2
[-√144+(-√64-√225]÷√2401/49
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Answer 1

Resposta:

Explicação passo-a-passo:

[(3^2)^3-3√-27]*(1/7)^-2 =

[ 3^6- 3]. 1/49

[729-3].1/49

726.1/49= 726/49

[-√144+(-√64-√225]÷√2401/49

[-12+(-8-15)]÷49/7

[-12+(-23)]÷49/7

[-12-23]÷49/7

-35÷49/7

-1/35. 49/7

-49/245= -1/5