Question

determine o valor da soma

√32+4√8-√50-(√2)³

Answer 1

√32+4√8-√50-(√2)³
$\sqrt{32}= \sqrt{2^5}=\sqrt{2^4*2}=4 \sqrt{2}$
$4 \sqrt{8}=4 \sqrt{2^3} =4 \sqrt{2^2*2} =8 \sqrt{2}$
$\sqrt{50}= \sqrt{2*5^2}=5 \sqrt{2}$
$\sqrt{2}^3= \sqrt{2^3}= \sqrt{2^2*2}=2 \sqrt{2}$

então, $\sqrt{32}+4 \sqrt{8}- \sqrt{50}-( \sqrt{2})^3 =4 \sqrt{2}+8 \sqrt{2} -5 \sqrt{2}-2 \sqrt{2}=5 \sqrt{2}$