Question

determine o valor da incógnita:
pfvrrrrr me ajudem ​

Answer 1

2^2 = y^2 + 1,2^2

y = $\sqrt{2,56} =1,6$

(x+1,5)^2 + 4,2^2 = 6,5^2

x^2 + 3x + 2,25 + 17,64 = 42,25

x^2 + 3x - 22,36 = 0

Delta = 6 + 89,44 = 95,44

x' = (-3 + 9,76 ) /2 = 3,38

x'' = (-3 - 9,76) /2 = Negativo, irrelevante

Logo,

x = 3,38

y = 1,6