Determine o valor da função quadratica
f(x)=-2x^2-3x+5 quando x=2
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Bom dia Luma!
Solução!
![f(x)=-2 x^{2} -3x+5\\\\\\\
f(2)=-2(2)^{2}-3(2)+5\\\\\\\
f(2)=-2.(4)-3(2)+5\\\\\\\\
f(2)=-8-6+5\\\\\\\
f(2)=-14+5\\\\\\\
\boxed{f(2)=-9}](https://tex.z-dn.net/?f=f%28x%29%3D-2+x%5E%7B2%7D+-3x%2B5%5C%5C%5C%5C%5C%5C%5C%0Af%282%29%3D-2%282%29%5E%7B2%7D-3%282%29%2B5%5C%5C%5C%5C%5C%5C%5C%0Af%282%29%3D-2.%284%29-3%282%29%2B5%5C%5C%5C%5C%5C%5C%5C%5C%0Af%282%29%3D-8-6%2B5%5C%5C%5C%5C%5C%5C%5C%0Af%282%29%3D-14%2B5%5C%5C%5C%5C%5C%5C%5C%0A%5Cboxed%7Bf%282%29%3D-9%7D+ "f(x)=-2 x^{2} -3x+5\\\\\\\
f(2)=-2(2)^{2}-3(2)+5\\\\\\\
f(2)=-2.(4)-3(2)+5\\\\\\\\
f(2)=-8-6+5\\\\\\\
f(2)=-14+5\\\\\\\
\boxed{f(2)=-9}")
Bom dia!
Bons estudos!
Solução!
Bom dia!
Bons estudos!
Respondido por
2
f(x)= -2x²-3x+5
f(2)=-2(2)²-3.(2)+5
f(2)=-2.4-6+5
f(2)=-8-6+5
f(2)=-14+5
f(2)=-9
f(2)=-2(2)²-3.(2)+5
f(2)=-2.4-6+5
f(2)=-8-6+5
f(2)=-14+5
f(2)=-9
cintitamat:
Muito Obrigado. Bons estudos!
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