Question

Determine o valor da função:
A)F(X)=4x X=3
B)G(X)=(1/3)X X=4
C)H(X)=(3raiz de 7) X=6
D)N(X)=(0,5)x X=-2
F)Q(X)= (4raiz de 3 ao cubo) X=-8/3

Answer 1

a)
$f \times 3 = 4 \times 3$
$3f =12$
$f = \frac{12}{3}$
$f =4$
b)
$g \times 4 = \frac{1}{3} \times 4$
$4g = \frac{4}{3}$
$g = \frac{4}{ \frac{3}{4} }$
$g = 4 \times \frac{4}{3}$
$g = \frac{16}{3}$
c)
$h \times 6 = 2 \sqrt{7}$
$6h = 2 \sqrt{7}$
$h = \frac{ 2\sqrt{7} }{6}$
d)
$n \times - 2 = 0.5 \times - 2$
$- 2n = - 1$
$- n = - \frac{1}{2}$
multiplique por -1
$n = \frac{1}{2}$
f)
$q \times - \frac{8}{3} = 4 \sqrt{ {3}^{3} }$
$- \frac{8}{3}q = 4 \sqrt{ {3}^{3} }$
$- \frac{8}{3}q = 4 \times 3 \sqrt{3}$
$- \frac{8}{3}q = 12 \sqrt{3} \\ q = \frac{12 \sqrt{3} }{ - \frac{8}{3} } \\ q = 12 \sqrt{3} \times - \frac{8}{3} \\ q = - \frac{12 \times 8 \sqrt{3} }{3} \\ q = \frac{86 \sqrt{3} }{3}$