Question

determine o valor da expressão y= tg 135°+sen210°+cos300°

URGENTE!!!!

Answer 1

Resposta:

tg135° = (90+45) = -cotg45° = -1

sen210° = (180+30) = -sen30° = -1/2

cos300° =(270+30) = +sec30°= 1/2

y= -1 +( -1/2 )+ 1/2

y= -1 -1/2 +1/2

y= -2 - 1 + 1/2

y= -3 + 1 /2

y= -2/2

y = -1