Question

determine o valor da expressão:

 

x2y2-xy3+y-1 para x=0,25 e y=0,5

 

me ajudem por favor

 

Answer 1

Olá, Joilma.

 

$<var>x=0,25=\frac14,y=0,5=\frac12\\\\ x^2y^2-xy^3+y-1=(\frac14)^2 \cdot (\frac12)^2-\frac14 \cdot (\frac12)^3+\frac12-1=\\\\ =\frac1{16} \cdot \frac14-\frac14 \cdot \frac18+\frac12-1=\frac1{64}-\frac1{32}+\frac12-1=\frac{1-2+32-64}{64}=\\\\ =-\frac{33}{64}</var>$

Answer 2

(25/100)^2(5/10)^2-0.25.(5/10)^3+5/10-1

 

1/16.1/4-1/4.1/8+1/2-1

1/64-1/32-1/2=-33/64