Question

determine o valor da expressão:
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Answer 1

$\begin{bmatrix}2&3&-2\\0&2&x\\2&x&-3\end{bmatrix}=2$

$-2{x}^{2}+6x-4=2\\-2{x}^{2}+6x-4-2=0\\-2{x}^{2}+6x-6=0\div(-2)\\{x}^{2}-3x+2=0$

$\Delta=9-8=1$

$x=\frac{3±1}{2} \\x'=2\\x''=1$