Question

determine o termo geral e calcule o valor de 06 no PG (3,9,27,...)

Answer 1

$\text{Termo geral}=a_1\cdot q^{n-1}$

$(3,9,27,\dots)$

$q=\dfrac{9}{3}=3$

$a_1=3$

$\text{Termo geral}=3\cdot 3^{n-1}=3^{n}$.

$a_6=3^{6}=729$

(3, 9, 27, 81, 243, 729)