Question

Determine o seno, cosseno e tangente do triângulo:

Escolha uma:
a. Sen B= 12/13 Cos B= 5/13 Tg B= 12/5
Sen C= 5/13 Cos C= 13/12 Tg C= 5/12

b. Sen B= 12/13 Cos B= 5/13 Tg B= 12/5
Sen C= 13/5 Cos C= 13/12 Tg C= 5/12

c. Sen B= 12/13 Cos B= 5/13 Tg B= 12/5
Sen C= 5/13 Cos C= 12/13 Tg C= 5/12

d. Sen B= 12/13 Cos B= 5/13 Tg B= 10/5
Sen C= 5/13 Cos C= 13/12 Tg C= 5/12

Answer 1

Resposta:

Alternativa carreta letra c)

Seno=c.o./h

Cosseno=c.a./h

tag=c.o/c.a

Answer 2

Explicação passo-a-passo:

Tamos que:

• $\sf sen~\hat{B}=\dfrac{cateto~oposto}{hipotenusa}$

$\sf \red{sen~\hat{B}=\dfrac{12}{13}}$

• $\sf cos~\hat{B}=\dfrac{cateto~oposto}{hipotenusa}$

$\sf \red{cos~\hat{B}=\dfrac{5}{13}}$

• $\sf tg~\hat{B}=\dfrac{cateto~oposto}{cateto~adjacente}$

$\sf \red{tg~\hat{B}=\dfrac{12}{5}}$

• $\sf sen~\hat{C}=\dfrac{cateto~oposto}{hipotenusa}$

$\sf \red{sen~\hat{C}=\dfrac{5}{13}}$

• $\sf cos~\hat{C}=\dfrac{cateto~oposto}{hipotenusa}$

$\sf \red{cos~\hat{C}=\dfrac{12}{13}}$

• $\sf tg~\hat{C}=\dfrac{cateto~oposto}{cateto~adjacente}$

$\sf \red{tg~\hat{C}=\dfrac{5}{12}}$

Letra C