Question

Determine o ponto V(xᵥ, yᵥ), vértice das parábolas:b) y = –x² + 4x – 3 *

(3, 1)

(2, 1)

(–2, 3)

(1, 2)

​

Answer 1

Resposta:

$\sf y = -x^{2} + 4x - 3$

$\sf ax^{2} + bx + c = 0$

$\sf a = - 1\\b = 4 \\c = - 3$

$\sf V_x = \dfrac{-b}{2a} = \dfrac{- 4}{2\times( - 1}) = \dfrac{- 4}{- 2} = 2$

$\sf v_y = \dfrac{- \Delta}{4a} = \dfrac{- [4^2 -4 \times (-1) \times (-3)]}{4\times (-1)} = \dfrac{-[16 - 12]}{- 4} = \dfrac{- 4 }{- 4} = 1$

V = { 2; 1 }

Explicação passo-a-passo: