Question

determine o ponto medio do segmento de extremidades a (1,-7) e b (3,-5) e depois (-1,5) e (5,-2)

Answer 1

Pm de a(1;-7) e b(3;-5)
Pmx = xa + xb / 2 Pmy = ya + yb /2
Pmx = 1 + 3 / 2 Pmy = -7 + (-5) / 2
Pmx = 2 Pmy = -6
Portanto o PM = (2;-6)

Pm de (-1;5) e (5;-2)
Pmx = -1 + 5 /2 Pmy = 5 + (-2) /2
Pmx = 2 Pmy = 3 / 2

PM = (2;1,5)