Question

determine o ponto medio do segmento AB em cada caso A(0-√2) e B(√3/3,2√2)

Answer 1

Resposta:

$x_A=0\\ y_A=-\sqrt{2} \\ \\ x_B={\sqrt{3} \over3}\\ \\ y_B=2\sqrt{2 } \\ \\ x_M={x_A+x_B\over2}={0+{\sqrt{3} \over3}\over2}={\sqrt{3} \over3}\div2={\sqrt{3} \over3}\times{1\over2}={\sqrt{3} \over6}\\ \\ y_M={y_A+y_B\over2}={-\sqrt{2} +2\sqrt{2} \over2}={\sqrt{2} \over2}\\ \\ Ponto~~m\'edio~~de~~AB\mapsto({\sqrt{3} \over6},{\sqrt{2} \over2})$