Question

Determine o perímetro do triângulo ABC, abaixo:

ME AJUDEM POR FAVOR!

Answer 1

Resposta:

$\textsf{Leia abaixo}$

Explicação passo a passo:

$\mathsf{\dfrac{c}{sen\:120\textdegree} = \dfrac{10}{sen\:30\textdegree}}$

$\mathsf{\dfrac{c}{\dfrac{\sqrt{3}}{2}} = \dfrac{10}{\dfrac{1}{2}}}$

$\mathsf{\dfrac{2c}{\sqrt{3}} = 20}$

$\mathsf{ 2c = 20\sqrt{3}}$

$\mathsf{ c = 10\sqrt{3}}$

$\mathsf{P = 10 + 10 + 10\sqrt{3}}$

$\mathsf{P = 20 + 10\sqrt{3}}$

$\boxed{\boxed{\mathsf{P \approx 37,32\:cm}}}\leftarrow\textsf{per{\'i}metro}$