Determine o número inteiro x que satisfaça cada igualdade:
a) x + (+10) = + 16
b) x + (-2) = -10
c) x + (+20) = 0
d) x +(-10) = +10
e) (+12) + x = -1
f) (-4) + x = +2
Gabrielguigui:
a=6
Soluções para a tarefa
Respondido por
11
a)x+(+10)= +16
x+10= +16
x= +16-10
x= +6
Verificando
x+(+10)= +16
+6+10= +16
+16= +16
b)x+(-2)= -10
x-2= -10
x= -10+2
x= -8
Verificando
x+(-2)= -10
-8+(-2)= -10
-8-2= -10
-10= -10
c)x+(+20)=0
x+20=0
x=0-20
x= -20
Verificando
x+(+20)=0
-20+20=0
0=0
d)x+(-10)= +10
x-10= +10
x= +10+10
x= +20
Verificando
x+(-10)= +10
+20+(-10)= +10
+20-10= +10
+10= +10
e)(+12)+x= -1
+12+x= -1
x= -1-12
x= -13
Verificando
(+12)+x= -1
(+12)+(-13)= -1
+12-13= -1
-1= -1
f)(-4)+x= +2
-4+x= +2
x= +2+4
x= +6
Verificando
(-4)+x= +2
(-4)+6= +2
-4+6= +2
+2= +2
x+10= +16
x= +16-10
x= +6
Verificando
x+(+10)= +16
+6+10= +16
+16= +16
b)x+(-2)= -10
x-2= -10
x= -10+2
x= -8
Verificando
x+(-2)= -10
-8+(-2)= -10
-8-2= -10
-10= -10
c)x+(+20)=0
x+20=0
x=0-20
x= -20
Verificando
x+(+20)=0
-20+20=0
0=0
d)x+(-10)= +10
x-10= +10
x= +10+10
x= +20
Verificando
x+(-10)= +10
+20+(-10)= +10
+20-10= +10
+10= +10
e)(+12)+x= -1
+12+x= -1
x= -1-12
x= -13
Verificando
(+12)+x= -1
(+12)+(-13)= -1
+12-13= -1
-1= -1
f)(-4)+x= +2
-4+x= +2
x= +2+4
x= +6
Verificando
(-4)+x= +2
(-4)+6= +2
-4+6= +2
+2= +2
Perguntas interessantes