determine o mmc pelo processo da decompociçao simutania mmm48 12 16 mmc 80 56
mmc 50 25 mmc 6 8 10 12 mmc 12 18 36 mmc 40 60
Soluções para a tarefa
Respondido por
5
48 ,12 ,16 | 2
24, 6 , 8 | 2
12, 3, 4 | 2
6, 3, 2 | 2
3, 3, 1 | 3
1, 1, 1| 2x2x2x2x3x3=48
80, 56 | 2
40, 28 | 2
20, 14 | 2
10, 7 | 2
5, 7 | 5
1, 7 | 7
1, 1 | 2x2x2x2x5x7=560
50, 25 | 2
25, 25 | 5
5, 5 | 5
1, 1 | 2x5x5=50
6, 8, 10, 12 | 2
3, 4, 5, 6 | 2
3, 2, 5, 3 | 2
3, 1, 5, 3, | 3
1, 1, 5, 1 | 5
1, 1, 1, 1 | 2x2x2x3x5=120
12, 18, 36 | 2
6, 9, 18 | 2
3, 9, 9 | 3
1, 3, 3 | 3
1, 1, 1 | 2x2x3x3=36
40, 60 | 2
20, 30 | 2
10, 15 | 2
5, 15| 3
5, 5 | 5
1, 1 | 2x2x2x3x5=120
24, 6 , 8 | 2
12, 3, 4 | 2
6, 3, 2 | 2
3, 3, 1 | 3
1, 1, 1| 2x2x2x2x3x3=48
80, 56 | 2
40, 28 | 2
20, 14 | 2
10, 7 | 2
5, 7 | 5
1, 7 | 7
1, 1 | 2x2x2x2x5x7=560
50, 25 | 2
25, 25 | 5
5, 5 | 5
1, 1 | 2x5x5=50
6, 8, 10, 12 | 2
3, 4, 5, 6 | 2
3, 2, 5, 3 | 2
3, 1, 5, 3, | 3
1, 1, 5, 1 | 5
1, 1, 1, 1 | 2x2x2x3x5=120
12, 18, 36 | 2
6, 9, 18 | 2
3, 9, 9 | 3
1, 3, 3 | 3
1, 1, 1 | 2x2x3x3=36
40, 60 | 2
20, 30 | 2
10, 15 | 2
5, 15| 3
5, 5 | 5
1, 1 | 2x2x2x3x5=120
Respondido por
2
48,12,16/2
24,6,8/2
12,3,4/2
6,3,2/2
3,3,1/3
1,1,1 2x2x2x2x3= 48
80,56/2
40,28/2
20,14/2
10,7/2
5,7/5
1,7/7
1,1 2x2x2x2x5x7= 560
50,25/2
25,25/5
5,5/5
1,1 2x5x5= 50
6,8,10,12/2
3,4,5,6/2
3,2,5,3/2
3,1,5,3/3
1,1,5,1/5
1,1,1,1 2x2x2x3x5= 120
12,18,36/2
6,9,18/2
3,9,9/3
1,3,3/3
1,1,1 2x2x3x3= 36
40,60/2
20,30/2
10,15/2
5,15/3
5,5/5
1,1 2x2x2x3x5= 120
24,6,8/2
12,3,4/2
6,3,2/2
3,3,1/3
1,1,1 2x2x2x2x3= 48
80,56/2
40,28/2
20,14/2
10,7/2
5,7/5
1,7/7
1,1 2x2x2x2x5x7= 560
50,25/2
25,25/5
5,5/5
1,1 2x5x5= 50
6,8,10,12/2
3,4,5,6/2
3,2,5,3/2
3,1,5,3/3
1,1,5,1/5
1,1,1,1 2x2x2x3x5= 120
12,18,36/2
6,9,18/2
3,9,9/3
1,3,3/3
1,1,1 2x2x3x3= 36
40,60/2
20,30/2
10,15/2
5,15/3
5,5/5
1,1 2x2x2x3x5= 120
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