Matemática, perguntado por sthephanny2089, 11 meses atrás

determine o m.m.c dos polinomios 8a, 6a²b, 12b³

Soluções para a tarefa

Respondido por robertocarlos5otivr9
1
8\text{a},6\text{a}^2,12\text{b}^3~|~2
4\text{a},3\text{a}^2,6\text{b}^3~~|~2
2\text{a},3\text{a}^2,3\text{b}^3~~|~2
\text{a},3\text{a}^2,3\text{b}^3~~~|~3
\text{a},\text{a}^2,\text{b}^3~~~~~~|~\text{a}
1,\text{a},\text{b}^3~~~~~~~|~\text{a}
1,1,\text{b}^3~~~~~~~|~\text{b}
1,1,\text{b}^2~~~~~~~|~\text{b}
1,1,\text{b}~~~~~~~~|~\text{b}
1,1,1

\text{mmc}(8\text{a},6\text{a}^2\text{b},12\text{b}^3)=2^3\cdot3\cdot\text{a}^2\cdot\text{b}^3=24\text{a}^2\text{b}^3
Respondido por GowtherBr
1
Vamos lá ...

Mmc( 8a, 6a²b, 12b³)

8a, 6a²b, 12b³ ! 2
4a, 3a²b, 6b³ ! 2
2a, 3a²b, 3b³ ! 2
a, 3a²b, 3b³ ! 3

a, a²b, b³ ! a
1 , ab , b³ ! a
1 , 1b , b³ ! b
1 , 1 , b² ! b
1 , 1 , b ! b
1 , 1 , 1

Mmc( 8a, 6a²b, 12b³) = 2^(3).3.a.a.b.b.b = 8*3*a^(2)*b^(3) = 24a^(2) b^(3)

Espero ter ajudado !!!
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