Question

determine o limite da função ​

Answer 1

$\frac{x {}^{2} - 4 }{x - 2} = \frac{(x + 2) \times (x - 2)}{x - 2} = x + 2$

ai calcula o limite de x+2 tendendo a 2

Answer 2

$\displaystyle\sf\lim_{ x \to 2}\dfrac{x^2-4}{x-2}=\lim_{x \to 2}\dfrac{\diagup\!\!\!\!\!(x-\diagup\!\!\!\!\!2)(x+2)}{\diagup\!\!\!\!\!(x-\diagup\!\!\!\!\!\!2)}\\\displaystyle\sf\lim_{x \to 2}(x+2)=2+2=4\checkmark$