Question

determine o gráfico de (x)=x²-4x-5;D(g)={0,1,2,3,4}​

Answer 1

Resposta:

raízes

x²-4x-5=0    ...a=1 ..conc. p/cima

f(0)=0-4*0-5=-5  ..ponto(0,-5)

f(1)=1²-4*1-5=1-4-5=-8    ..ponto (1,-8)

f(2)=2²-4*2-5 =4-8-5=-9  ..ponto (2,-9)

f(3)=3²-4*3-5 =9-12-5=-8  ..ponto (3,-8)

f(4)=16-4*4-5 =16-16-5=0 ..ponto (4,-5)