Question

DETERMINE O DOMINIO DA FUNCAO

a) f(x)= 4x/√(2x-6)

Answer 1

Resposta:

$\frac{4x}{\sqrt{2x-6}}\\\\=\frac{4x\sqrt{2x-6}}{\sqrt{2x-6}\sqrt{2x-6}}\\\\=\frac{4x\sqrt{2x-6}}{2x-6}\\\\=\frac{4x\sqrt{2x-6}}{2\left(x-3\right)}\\\\=\frac{2x\sqrt{2x-6}}{\left(x-3\right)}\\\\=\frac{2x\sqrt{2x-6}}{x-3}$