Question

determine o delta da equacao
$3x ^{2} + 18x - 15 = 0$

Answer 1

3x^2 + 18x - 15 = 0

a = 3; b = 18; c = - 15

∆ = b^2-4ac

∆ = 18^2 - 4.3.(-15)

∆ = 324 + 12.15

∆ = 324 + 180

∆ = 504

√∆ = √36.√14

√∆ = 6√14

504: 2

252: 2

126: 2

63: 3

21: 3

7: 7

1

R.: ∆ = 504