Question

determine o décimo termo da PG (1/64, -1/32, ... )​

Answer 1

a₂=-1/32=-2⁻⁵

a₁₀=?

$q = \frac{ - \frac{ 1}{32} }{ \frac{1}{64} } = - \frac{1}{32}.64 = - 2$

a₁₀=a₂.q⁸

a₁₀= (-2)⁻⁵.(-2)⁸=(-2)⁻⁵⁺⁸=(-2)³=-8