Question

Determine o conjunto verdade da equação(2X alquadrado-8X+6=0

Answer 1

$2x^{2} -8x+6=0\\ \\a=2\ b=-8\  c=6\\ \\x=\frac{-b\pm \sqrt{b^{2}-4ac} }{2a} =\frac{-(-8)\pm \sqrt{(-8)^{2}-4\cdot2\cdot6} }{2\cdot2} =\frac{8\pm \sqrt{64-48} }{4} \\=\frac{8\pm \sqrt{16} }{4} =\frac{8\pm 4}{4}\\ \\x'=\frac{8+4}{4}=\frac{12}{4}=3\\\\x''=\frac{8-4}{4}=\frac{4}{4}=1\\ \\S=\{1,\ 3\}$

Answer 2

2X²-8X+6=0

X= 8+-√8²-4.2.6

/2.2

X= 8+√64-48

/4

X= 8+-√16

/4

X= 8+- 4

/4

X1= 8+4

/4

X1= 3

X2= 8-4

/4

X2= 1