Question

Determine o conjunto solução log 4(x+1)=2

Answer 1

$log _{4} ^{(x + 1)} = 2$
$4^{2} = x+1$
x = 15

V = {x∈r / x = 15 }

Answer 2

$Resolu\c{c}\~ao \to \left\{\begin{array}{ccc}log_4\ (x+1) = 2\\\\4^2 = x+1\\\\16 = x+1\\\\\boxed{\boxed{x = 15}}\\\\S = \{15\}\end{array}\right$

Espero ter ajudado. :))