determine o conjunto soluçao das equaçao aplicando a regra de sarus
1 x 1
-2 -4 2 = 0
4 8 3
Soluções para a tarefa
Respondido por
2
Olá Michely,
aplicando o mesmo método de resolução para acharmos o determinante de 3ª ordem (regra de Sarruz), teremos:
![\left|\begin{array}{ccc}1&x&1\\-2&-4&2\\4&8&3\end{array}\right| \left\begin{array}{ccc}1&x\\-2&-4\\4&8\end{array}\right=0\\\\\\
-12+8x-16+16-16+6x=0\\\\
-12-16+8x+6x=0\\\\
-12-16=-8x-6x\\\\
-28=-14x\\\\
~~~~x= \dfrac{-28}{-14}\\\\
~~~~x=2\\\\
\boxed{S=\{2\}} \left|\begin{array}{ccc}1&x&1\\-2&-4&2\\4&8&3\end{array}\right| \left\begin{array}{ccc}1&x\\-2&-4\\4&8\end{array}\right=0\\\\\\
-12+8x-16+16-16+6x=0\\\\
-12-16+8x+6x=0\\\\
-12-16=-8x-6x\\\\
-28=-14x\\\\
~~~~x= \dfrac{-28}{-14}\\\\
~~~~x=2\\\\
\boxed{S=\{2\}}](https://tex.z-dn.net/?f=++%5Cleft%7C%5Cbegin%7Barray%7D%7Bccc%7D1%26amp%3Bx%26amp%3B1%5C%5C-2%26amp%3B-4%26amp%3B2%5C%5C4%26amp%3B8%26amp%3B3%5Cend%7Barray%7D%5Cright%7C++%5Cleft%5Cbegin%7Barray%7D%7Bccc%7D1%26amp%3Bx%5C%5C-2%26amp%3B-4%5C%5C4%26amp%3B8%5Cend%7Barray%7D%5Cright%3D0%5C%5C%5C%5C%5C%5C%0A-12%2B8x-16%2B16-16%2B6x%3D0%5C%5C%5C%5C%0A-12-16%2B8x%2B6x%3D0%5C%5C%5C%5C%0A-12-16%3D-8x-6x%5C%5C%5C%5C%0A-28%3D-14x%5C%5C%5C%5C%0A%7E%7E%7E%7Ex%3D+%5Cdfrac%7B-28%7D%7B-14%7D%5C%5C%5C%5C%0A%7E%7E%7E%7Ex%3D2%5C%5C%5C%5C%0A%5Cboxed%7BS%3D%5C%7B2%5C%7D%7D+++)
aplicando o mesmo método de resolução para acharmos o determinante de 3ª ordem (regra de Sarruz), teremos:
Perguntas interessantes