Question

Determine o conjunto solução da inequação: $3x- \frac{1}{2}>2x+ \frac{2}{3}$ Ajuda?

Answer 1

$3x-\dfrac{1}{2}>2x+\dfrac{2}{3}$

$3x-2x>\dfrac{2}{3}+\dfrac{1}{2}$

$x>\dfrac{2\cdot2+1\cdot3}{6}$

$x>\dfrac{4+3}{6}$

$x>\dfrac{7}{6}$

$S=\{x\in\mathbb{R}~|~x>\dfrac{7}{6}\}$

Answer 2

$3x-\frac{1}{2}>2x+\frac{2}{3}\\ \\ 3x-2x>\frac{2}{3}+\frac{1}{2}\\ \\ x>\frac{4}{6}+\frac{3}{6}\\ \\ \boxed{x>\frac{7}{6}}$