Question

Determine o conjunto solução da equação x^(2) + 6x + 8 = 0

Answer 1

x² + 6x + 8 = 0
a = 1; b = 6; c = 8

Δ = b² - 4ac
Δ = 6² - 4.1.8
Δ = 36 - 32
Δ = 4

x = - b +/- √Δ
        2a

x = - 6 + 2 = -4/2 = - 2
          2

x = - 6 - 2 = -8/2 = - 4
          2

R.: x = - 2 e x = - 4

Answer 2

$x^2 + 6x + 8 = 0\\\\\\ a=1;b=6;c=8\\\\\\ \Delta=b^2-4ac\to \Delta=6^2-4*1*8\to \Delta=36-32\to \Delta=4\\\\\\ x= \frac{-b+- \sqrt{\Delta} }{2a} \to x= \frac{-6+- \sqrt{4} }{2*1} \to x= \frac{-6+- 2 }{2} \to \\ \\\\ x'=\frac{-6+2 }{2} \to x'=\frac{-4 }{2} \to x'=-2\\\\\\ x''=\frac{-6-2 }{2} \to x''=\frac{-8 }{2} \to x''=-4\\\\\\ S=(-4;-2)$