Question

Determine o conjunto solução da equação (2x²- 4)² -8(2x²-4) = 0

Answer 1

Explicação passo-a-passo:

(2x²-4)²-8(2x²-4)=0

(2x²-4).(2x²-4)-8(2x²-4)=0

4x²-8x²-6x²+16-16x²+32=0

-26x²+48=0 (-1)

26x²-48=0

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A=26

B=0

C=(-48)

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DELTA:◇=B²-4.A.C

◇=0²-4.26.(-48)

◇=4992

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BASKARA:

$x \frac{ - b - + \sqrt{delta} }{2 \times a}$

$x \ \frac{0 - + \sqrt{4992} }{2 \times a}$

$x \ \frac{0 - + \sqrt{ {2}^{7} \times 3 \times 13} }{52}$

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X' E X":

${x}^{1} \ \frac{0 + 2 \sqrt{39} }{52}$

DA PARA DIVIDIR O 2 E O 52 POR 2

${x}^{1} \ \frac{</u></strong><strong><u>1</u></strong><strong><u> </u></strong><strong><u>\sqrt{39} }{</u></strong><strong><u>2</u></strong><strong><u>6</u></strong><strong><u>}$

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${x}^{2} \ \frac{0 - 2 \sqrt{39} }{52}$

DA PARA DIVIDIR O 2 E O 52 POR 2

${x}^{2} \ \frac{ - </u></strong><strong><u>1</u></strong><strong><u> \sqrt{39} }{</u></strong><strong><u>2</u></strong><strong><u>6</u></strong><strong><u>}$

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CONJUNTO SOLUÇÃO:

$s \ \frac{ - </u></strong><strong><u>1</u></strong><strong><u> \sqrt{39} }{</u></strong><strong><u>2</u></strong><strong><u>6</u></strong><strong><u>} | \frac{ + </u></strong><strong><u>1</u></strong><strong><u> \sqrt{39} }{</u></strong><strong><u>2</u></strong><strong><u>6</u></strong><strong><u>}$