Question

determine o coeficiente angular da reta que passa pelo ponto P -5,- 2 e pelo ponto médio do segmento A 2,6 e B 4,10​

Answer 1

Cálculo do ponto médio de A e B:

$\mathtt{x_{M}=\dfrac{x_{A}+x_{B}}{2}}\\\mathtt{x_{M}=\dfrac{2+4}{2}=3}$

$\mathtt{y_{M}=\dfrac{y_{A}+y_{B}}{2}}\\\mathtt{y_{M}=\dfrac{6+10}{2}=\dfrac{16}{2}=8}$

O coeficiente angular da reta passa pelos pontos

M(3,2) e P(-5,-2)

$\mathtt{m=\dfrac{y_{P}-y_{M}}{x_{P}-x_{M}}}\\\mathtt{m=\dfrac{-2-2}{-5-3}}\\\mathtt{m=\dfrac{-4\div4}{-8\div4}}$

$\boxed{\boxed{\mathtt{m=\dfrac{1}{2}}}}$