Determine o centro C e a medida R do raio das circunferências a seguir a) x² - 6x + y² - 8y = 144 b) x² + y² - 6x – 2y = 0
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a)x2−6x+y2−8y−144=0
(1)⋅x2+(−6)⋅x+(y2−8y−144)=0
x=−(−6)±(−6)2−4⋅(y2−8y−144)−−−−−−−−−−−−−−−−−−−−−−√2
x=6±36−(4y2−32y−576)−−−−−−−−−−−−−−−−−−√2
x=6±−4y2+32y+612−−−−−−−−−−−−−−−√2
x=6±(2)⋅−y2+8y+153−−−−−−−−−−−−−√2
x=(2)⋅[(3)±−y2+8y+153−−−−−−−−−−−−−√](2)
x1=3+−y2+8y+153−−−−−−−−−−−−−√
x2=3−−y2+8y+153−−−−−−−−−−−−−√
b)2−6x+y2−2y=0
(1)⋅x2+(−6)⋅x+(y2−2y)=0
x=−(−6)±(−6)2−4⋅(y2−2y)−−−−−−−−−−−−−−−−−√2
x=6±36−(4y2−8y)−−−−−−−−−−−−−√2
x=6±−4y2+8y+36−−−−−−−−−−−−−√2
x=6±(2)⋅−y2+2y+9−−−−−−−−−−−√2
x=(2)⋅[(3)±−y2+2y+9−−−−−−−−−−−√](2)
x1=3+−y2+2y+9−−−−−−−−−−−√
x2=3−−y2+2y+9−−−−−−−−−−−√
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