Question

Determine o 6° termo da PG infinita (10, 4, 8/5...)

Answer 1

a1 = 10
a2 = 4
a3 = 8/5
q = 4/10 = 2/5 ***
a6 = a1q⁵
a6 = 10 * (2/5)⁵
a6 = 10 /1 * 32/3125  = 320/3125 = 64/625 ****
a1 = 10
a2 = 10*2/5 = 20/5 = 4
a3 = 4 * 2/5 = 8/5
a4 = 8/5 * 2/5 = 16/25 ***
a5 = 16/25 * 2/5 = 32/ 125
a6 = 32/125 * 2/5 = 64/125 **** confere