Question

Determine o 37º termo da PA (-8, 3, 14, ...)?

Answer 1

$\boxed{a_n=a_k+(n-k)r}$

$\left\{a_1,a_2,a_3,\dots\right\}\equiv\left\{-8,3,14,\dots\right\}$

$a_2=a_1+r\ \to\ r=a_2-a_1=3-(-8)\ \therefore\ \boxed{r=11}$]

$a_{37}=a_1+36r=-8+36(11)\ \to\ \boxed{a_{37}=388}$