Question

determine o 15° termo da pg 384, 192, 96...

Answer 1

$\boxed{\mathsf{q=\frac{a_{n}}{a_{(n-1)}}}}$

192/384

1/2

$\boxed{\mathsf{A_{n}=a_{m}\cdot q^{(n-m)}}}$

a₁₅ = 384 * (1/2)⁽¹⁵⁻¹⁾

a₁₅ = 384/16384

a₁₅ = 3/128