determine matriz A=[aij]3×3,tal que aij=i-3j+2.
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Bom dia!
Vamos lá:
a11=1+3*1+2=6
a12=1+3*2+2=9
a13=1+3*3+2=12
a21=2+3*1+2=7
a22=2+3*2+2=10
a23=2+3*3+2=13
a31=3+3*1+2=8
a32=3+3*2+2=11
a33=3+3*3+2=14
![A= \left[\begin{array}{ccc}6&9&12\\7&10&13\\8&11&14\end{array}\right]](https://tex.z-dn.net/?f=A%3D++%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D6%26amp%3B9%26amp%3B12%5C%5C7%26amp%3B10%26amp%3B13%5C%5C8%26amp%3B11%26amp%3B14%5Cend%7Barray%7D%5Cright%5D+ "A= \left[\begin{array}{ccc}6&9&12\\7&10&13\\8&11&14\end{array}\right]")
Vamos lá:
a11=1+3*1+2=6
a12=1+3*2+2=9
a13=1+3*3+2=12
a21=2+3*1+2=7
a22=2+3*2+2=10
a23=2+3*3+2=13
a31=3+3*1+2=8
a32=3+3*2+2=11
a33=3+3*3+2=14
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