Question

Determine M ponto medio de AB nos casos
A) a(8,-2) b(-9,-6)​

Answer 1

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$\large\boxed{\begin{array}{l}\sf Sejam~A(x_A,y_A)~e~B(x_B,y_B)~dois~pontos~quaisquer\\\sf do ~plano~cartesiano.O~ponto~m\acute edio~de~A~e~B\\\sf \acute e~o~segmento~M(x_M,y_M)~tal~que\\\sf \boxed{\boxed{\boxed{\boxed{\sf x_M=\dfrac{x_A+x_B}{2}}}}}~\sf e~\boxed{\boxed{\boxed{\boxed{\sf y_M=\dfrac{y_A+y_B}{2}}}}}\end{array}}$

$\boxed{\begin{array}{l}\sf A(8,-2)~B(-9,-6)\\\sf x_A=8\\\sf y_A=-2\\\sf x_B=-9\\\sf y_B=-6\\\underline{\rm soluc_{\!\!,}\tilde ao\!:}\\\sf x_M=\dfrac{x_A+x_B}{2}\\\sf x_M=\dfrac{8+(-9)}{2}\\\sf x_M=\dfrac{8-9}{2}\\\sf x_M=-\dfrac{1}{2}\\\sf y_M=\dfrac{y_A+y_B}{2}\\\sf y_M=\dfrac{(-2)+(-6)}{2}\\\sf y_M=\dfrac{-2-6}{2}\\\sf y_M=\dfrac{-8}{2}\\\sf y_M=-4\\\huge\boxed{\boxed{\boxed{\boxed{\sf M\bigg(-\dfrac{1}{2},-4\bigg)}}}}\end{array}}$