Question

Determine essa equação com formula de Bhaskara.
$- 2 {x}^{2} + 8x - 6 = 0$

Answer 1

∆=8²-4.(-2).(-6)
∆=64+8.(-6)
∆=64-48
∆=16

x=-(+8) +- √16/2.-2
x=-8+-4/-4

x¹=-8+4/-4
x¹=-4/-4
x¹=1

x²=-8-4/-4
x²=-12/-4
x²=3

Answer 2

a= -2 b= 8 c= -6
Δ=b^2-4ac
Δ=8^2-4.(-2).(-6)
Δ=64 - 48
Δ= 16

-b +- √Δ/2a
-8 +- √16/2.(-2)
-8 +- 4/-4 
x'= -8+4/-4 = -4/-4 = 1
x" = -8-4/4 = -12/-4 = 3