Matemática, perguntado por estellamendes, 7 meses atrás

determine em cada figura o valor de x. URGENTE PARA HJ!

Anexos:

Soluções para a tarefa

Respondido por gabrielhiroshi01
1

Explicação passo-a-passo:

Utilizando potência de ponto nas figuras:

\overline{PA}.\overline{PB}=\overline{PC}.\overline{PD}

b)

2x.x=9.2\\\\2x^{2} =18\\\\x^{2} =\dfrac{18}{2} \\\\x^{2} =9\\\\x=\pm\sqrt{9} \\\\x=\pm3\\\\\boxed{x=3 \, \ \text pois\ x>0}

c)

6.12=x.4\\\\4x=72\\\\x=\dfrac{72}{4} \\\\\boxed{x=18}

e)

(3+x).1=3.2\\\\3+x=6\\\\x=6-3\\\\\boxed{x=3}

f)

(x-1).2x=(3x-4).x\\\\2x^{2} -2x=3x^{2} -4x\\\\3x^{2} -4x-2x^{2} +2x=0\\\\x^{2} -2x=0\\\\x(x-2)=0\\\\x=0\\\text ou\\x-2=0\\\\x=2\\\\\boxed{x=2 \ , \text pois\ x>0}

h)

x.8=6.(18-6)\\\\8x=6.12\\\\8x=72\\\\x=\dfrac{72}{8} \\\\\boxed{x=9}

i)

2x.x=8.9\\\\2x^{2} =72\\\\x^{2} =\dfrac{72}{2} \\\\x^{2} =36\\\\x=\pm\sqrt{36} \\\\x=\pm 6\\\\\boxed{x=6 \ , \text pois\  x>0}

k)

x.x=3.27\\\\x^{2} =81\\\\x=\pm\sqrt{81}\\\\x=\pm 9\\\\\boxed{x=9 \ , \text pois\ x>0}

l)

x.(4x-1)=(x+1).3x\\\\4x^{2} -x=3x^{2} +3x\\\\4x^{2} -x-3x^{2} -3x=0\\\\x^{2} -4x=0\\\\x(x-4)=0\\\\x=0\\\\\tetx ou\\\\x-4=0\\\\x=4\\\\\boxed{x=4\ , \text pois\ x>0}

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