Determine, caso existam, os zero de cada da função
ME EXPLICA COMO VOCÊ FEZ
d) f(x)=-1/2x²+6
Soluções para a tarefa
Respondido por
0
Rodrigo, mesmo processo da tarefa anterior que tinha me pedido:
![f(x)=- \dfrac{1}{2} x^2+6\\\\ - \dfrac{1}{2} x^2+6=0\to\\\\ - \dfrac{1}{2} x^2=-6~(-1)\to\\\\ \dfrac{1}{2} x^2=6\to\\\\ x^{2} = \dfrac{6}{\dfrac{1}{2}} \to\\\\\\ x^{2} =6\times2\to\\\\ x^2=12\to\\\\ x=\pm \sqrt{12} \to\\\\ x=\pm \sqrt{2^2\times3} \to\\\\ x=\pm 2\sqrt{3}\\\\\\\\ \large\boxed{\boxed{S=\{ -2\sqrt{3}~;~2\sqrt{3}\}}} f(x)=- \dfrac{1}{2} x^2+6\\\\ - \dfrac{1}{2} x^2+6=0\to\\\\ - \dfrac{1}{2} x^2=-6~(-1)\to\\\\ \dfrac{1}{2} x^2=6\to\\\\ x^{2} = \dfrac{6}{\dfrac{1}{2}} \to\\\\\\ x^{2} =6\times2\to\\\\ x^2=12\to\\\\ x=\pm \sqrt{12} \to\\\\ x=\pm \sqrt{2^2\times3} \to\\\\ x=\pm 2\sqrt{3}\\\\\\\\ \large\boxed{\boxed{S=\{ -2\sqrt{3}~;~2\sqrt{3}\}}}](https://tex.z-dn.net/?f=f%28x%29%3D-+%5Cdfrac%7B1%7D%7B2%7D+x%5E2%2B6%5C%5C%5C%5C+-+%5Cdfrac%7B1%7D%7B2%7D+x%5E2%2B6%3D0%5Cto%5C%5C%5C%5C+-+%5Cdfrac%7B1%7D%7B2%7D+x%5E2%3D-6%7E%28-1%29%5Cto%5C%5C%5C%5C+%5Cdfrac%7B1%7D%7B2%7D+x%5E2%3D6%5Cto%5C%5C%5C%5C+x%5E%7B2%7D+%3D+%5Cdfrac%7B6%7D%7B%5Cdfrac%7B1%7D%7B2%7D%7D+%5Cto%5C%5C%5C%5C%5C%5C+x%5E%7B2%7D+%3D6%5Ctimes2%5Cto%5C%5C%5C%5C+x%5E2%3D12%5Cto%5C%5C%5C%5C+x%3D%5Cpm+%5Csqrt%7B12%7D+%5Cto%5C%5C%5C%5C+x%3D%5Cpm+%5Csqrt%7B2%5E2%5Ctimes3%7D+%5Cto%5C%5C%5C%5C+x%3D%5Cpm+2%5Csqrt%7B3%7D%5C%5C%5C%5C%5C%5C%5C%5C+%5Clarge%5Cboxed%7B%5Cboxed%7BS%3D%5C%7B+-2%5Csqrt%7B3%7D%7E%3B%7E2%5Csqrt%7B3%7D%5C%7D%7D%7D+)
Perguntas interessantes
O inverso de 1/2 é 2