Question

Determine caso exista zeros da funções: f(x)= x²-6x+9, f(x)=2x²+3x-5

Answer 1

a) x^2-6x+9=0
∆=36-36
∆= 0
x'=x"= -b/2a
x'=x"= 6/2= 3

b) 2x^2+3x-5=0
∆= 9+4*2"5
∆= 9+40
∆= 49
x= -3 +ou -√49/2*2
x'=-3+7/4
x'= 4/4= 1
x"= -3-7/4
x"= -10/4
x"= -5/2