Question

Determine as vertices

f(x)= 2x^2 + 4x - 3

Answer 1

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Answer 2

Explicação passo-a-passo:

$f(x)=2x^2+4x-3$

$\bullet~~x_V=\dfrac{-b}{2a}$

$x_V=\dfrac{-4}{2\cdot2}$

$x_V=\dfrac{-4}{4}$

$x_V=-1$

$\bullet~~y_V=\dfrac{-\Delta}{4a}$

$\Delta=4^2-4\cdot2\cdot(-3)$

$\Delta=16+24$

$\Delta=40$

$y_V=\dfrac{-40}{4\cdot2}$

$y_V=\dfrac{-40}{8}$

$y_V=-5$

Logo, $V(-1,-5)$