Question

DETERMINE AS SOLUÇÕES REAIS DAS EQUAÇÕES
A)-3x²-10x-3=0

B)t²+6t+9=0

C)x²-2x-3=0

D)2x²-3x+1=0

Answer 1

a) -3x^2-10x-3=0
delta=b^2-4.a.c
delta=(-10)^2-4.(-3).(-3)
delta=100-36
delta=64
x=-b-/+ raiz de delta / 2a
x=-(-10)-8/2.(-3)
x=10-8/-6
x=6/-6
x=-1
x=-(-10)+8/2.(-3)
x=10+8/-6
x=18/-6
x=-3
b) t^2+6t+9=0
delta=b^2-4.a.c
delta=6^2-4.1.9
delta=36-36
delta=0
t=-b-/+ raiz de delta / 2a
t=-6-0/2.1
t=-6/2
t=-3
c) x^2-2x-3=0
delta=b^2-4.a.c
delta=(-2)^2-4.1.(-3)
delta=4+12
delta=16
x=-b-/+ raiz de delta/2a
x=-(-2)-4/2.1
x=2-4/2
x=-2/2
x=-1
x=-(-2)+4/2.1
x=2+4/2
x=6/2
x=3
d) 2x^2-3x+1=0
delta=b^2-4.a.c
delta=(-3)^2-4.2.1
delta=9-8
delta=1
x=-b-/+ raiz de delta / 2a
x=-(-3)-1/2.2
x=3-1/4
x=2/4
x=0,5
x=-(-3)+1/2.2
x=3+1/4
x=4/4
x=1