Question

determine as raizes
-xelevado ao quadrado -7x+12=0

Answer 1

-x^2-7x+12=0
delta=b^2-4.a.c
delta=(-7)^2-4.(-1).12
delta=49-48
delta=1
x=-b-/+ raiz de delta/2a
x=-(-7)-1/2.(-1)
x=7-1/-2
x=6/-2
x=-3
x=-(-7)+1/2.(-1)
x=7+1/-2
x=8/-2
x=-4

Answer 2

x² - 7x + 12 = 0

a = 1
b = - 7
c = 12

Δ = b² - 4ac
Δ = (-7)² - 4.1.12
Δ = 49 - 48
Δ = 1

x = - b +/- √Δ
         2.a

x' = - (-7) + √1  = 7 + 1 = 8/2 = 4     
          2.1             2

x" = - (-7) - √1 = 7 - 1 = 6/2 = 3
            2.1         2