Question

Determine as raízes e o vértice das funções:
y= -3x^2+10x -3

y=5x^2 - 4x - 1

Answer 1

espero ter ajudado

a primeira

3x2−10x+y+3=0

(3)⋅x2+(−10)⋅x+(y+3)=0

x=−(−10)±(−10)2−4⋅(3)⋅(y+3)−−−−−−−−−−−−−−−−−−−−√2⋅(3)

x=10±100−(12y+36)−−−−−−−−−−−−−√6

x=10±−12y+64−−−−−−−−−√6

x=10±(2)⋅−3y+16−−−−−−−−√6

x=(2)⋅[(5)±−3y+16−−−−−−−−√](2)⋅(3)

x1=5+−3y+16−−−−−−−−√3

x2=5−−3y+16−−−−−−−−√3

a segunda

−5x2+4x+y+1=0

(−5)⋅x2+(4)⋅x+(y+1)=0

x=−(4)±(4)2−4⋅(−5)⋅(y+1)−−−−−−−−−−−−−−−−−−−√2⋅(−5)

x=−4±16−(−20y−20)−−−−−−−−−−−−−−−√−10

x=4±20y+36−−−−−−−√10

x=4±(2)⋅5y+9−−−−−√10

x=(2)⋅[(2)±5y+9−−−−−√](2)⋅(5)

x1=2+5y+9−−−−−√5

x2=2−5y+9−−−−−√5