Question

Determine as raízes de x2_14x+40=0

Answer 1

x² - 14x + 40 = 0
a = 1, b = - 14, c = 40

Δ = b² - 4ac
Δ = (- 14)² - 4 . 1 . 40
Δ = 196 - 160
Δ = 36

x = (- b ± √Δ)/2a
x = (- (- 14) ± √36)2 . 1
x = (14 ± 6)/2

x' = (14 + 6)/2 = 20/2 = 10
x'' = (14 - 6)/2 = 8/2 = 4

x = 10, x = 4