Question

determine as raízes das equações utilizando a fórmula resolutiva.​

Answer 1

a) 3x² - 4x + 1 = 0

a = 3

b = - 4

c = 1

∆ = b² - 4 . a . c

∆ = (-4)² - 4 . 3 . 1

∆ = 16 - 12

∆ = 4

x = - b ± √∆

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2a

x' = - (-4) - 4

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2 . 3

x' = 4 - 4

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6

x' = 0

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6

x' = 0

x" = - (-4) + 4

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2 . 3

x" = 4 + 4

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6

x" = 8 (÷2)

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6 (÷2)

x" = 4

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3

S = {0 , 4/3}

b) x² - 6x + 9 = 0

a = 1

b = - 6

c = 9

∆ = b² - 4 . a . c

∆ = (-6)² - 4 . 1 . 9

∆ = 36 - 36

∆ = 0

x = - b ± √∆

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2a

x = - (-6) - 0

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2 . 1

x = 6 - 0

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2

x = 6

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2

x = 3

S = {3}