Question

determine as raizes das equações 12x²-10x-8=0



B)x²-6x+8=0:



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Answer 1

Resposta:

a- f(x)= 12x²-10x-8=0 a=12/b=-10 /c=-8

∆=b²-4ac

∆= (-10)² -4.(12).(-8)

∆= 100+384

∆=484

x= -b± √∆

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2a

x= -(-10) ± √484

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2.(12)

x= 10±22

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24

x¹= 10+22 = 32 = 4

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24 24 3

x²= 10-22 = -11

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24 24

b- f(x)= x²-6x+8 a=1 /b=-6 / c=8

∆=b²-4ac

∆= (-6)² -4.(1).(8)

∆= 36-32

∆= 4

x= -b±√∆

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2a

x= -(-6) ± √4

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2.(1)

x= 6±2

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2

x¹= 6+2 = 8 = 4

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2 2

x²= 6-2 = 4 = 2

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2 2